linq和ef关于group by取最大值的两种写法


LINQ:

var temp = from p in db.jj_Credentials
                       group p by p.ProfessionID into g
                       select new
                       {
                           g.Key,
                           MaxPrice = g.Max(p => p.CredentialsRankID)
                       };

EF:

var temp1 = db.jj_Credentials.GroupBy(m => m.ProfessionID).Select(m => m.Max(o => o.CredentialsRankID));
            foreach(var p in temp1)
            {
                Response.Write(p);
            }

补充:取最大值后取得当前完整记录的方法,两种写法:

写法1

//写法1
            var list1 = db.jj_Credentials.Where(m => m.UserId == UserContext.UserID && m.IsAudit).OrderByDescending(m => m.CredentialsRankID).ToList().GroupBy(x => x.ProfessionID)
                .SelectMany(t => t.Select((b, i) => new { b, i }).Where(m => m.i == 0)).Select(m => m.b);
            
            foreach (var i in list1)
            {
                Response.Write(string.Format("{0} {1} {2} {3}<br>", i.CredentialsID, i.UserId, i.CredentialsRankID, i.ProfessionID));
            }

写法2

//写法2
            var list = db.jj_Credentials.Where(m => m.UserId == UserContext.UserID && m.IsAudit).OrderByDescending(x => x.CredentialsRankID).ToList().GroupBy(x => x.ProfessionID)
            .Select(g => new { g, count = g.Count() })
            .SelectMany(t => t.g.Select(b => b).Zip(Enumerable.Range(1, t.count), (j, i) =>
                new
                {
                    CredentialsID = j.CredentialsID,
                    UserID = j.UserId,
                    CredentialsRankID = j.CredentialsRankID,
                    ProfessionID = j.ProfessionID,
                    rn = i
                }).Where(x => x.rn == 1));

            //打印
            foreach (var i in list)
            {
                Response.Write(string.Format("{0} {1} {2} {3}<br>", i.CredentialsID, i.UserID, i.CredentialsRankID, i.ProfessionID));
            }

 


免责声明!

本站转载的文章为个人学习借鉴使用,本站对版权不负任何法律责任。如果侵犯了您的隐私权益,请联系本站邮箱yoyou2525@163.com删除。



 
粤ICP备18138465号  © 2018-2025 CODEPRJ.COM