C# asp.net 中sql like in 参数化

Like 参数：
string strSql = "select * from Person.Address where City like '%@add%'";
SqlParameter[] Parameters=new SqlParameter[1];
Parameters[0] = new SqlParameter("@add", "bre");

In 参数
string strSql = "select * from Person.Address where AddressID in (@add)";
SqlParameter[] Parameters = new SqlParameter[1];
Parameters[0] = new SqlParameter("@add", "343,372,11481,11533,11535,11755,11884,12092,12093,12143");

可是这样放在程序里面是无法执行的，即使不报错，也是搜索不出来结果的，
去网上搜索也没有一个明确的答案，经过反复试验，终于解决这个问题
正确解法如下：

like 参数
string strSql = "select * from Person.Address where City like '%'+ @add + '%'";
SqlParameter[] Parameters=new SqlParameter[1];
Parameters[0] = new SqlParameter("@add", "bre");
 
in 参数
string strSql = "exec('select * from Person.Address where AddressID in ('+@add+')')";
SqlParameter[] Parameters = new SqlParameter[1];
Parameters[0] = new SqlParameter("@add", "343,372,11481,11533,11535,11755,11884,12092,12093,12143");

 

 

转自http://blog.csdn.net/maolixian/article/details/6166282