问题：（DRIVING.search是异步操作）
for循环中做异步操作会导致aDistances数组里边的数据全部都是从A_SHOP_INFO数组中最后一条数据获取的值。
var iIdx = 0; for(var i=0, len=A_SHOP_INFO.length; i<len; i++){ var shopInfo = A_SHOP_INFO[i]; DRIVING.search(new AMap.LngLat(shopInfo.shop_location_long,shopInfo.shop_location_lat), new AMap.LngLat(myLnglat[0],myLnglat[1]), function(status, result){ var distance = new O_DISTANCE_INFO(); distance.distance = result.routes[0]["distance"]; distance.shop_id = shopInfo.shop_id; distance.shop_location_long = shopInfo.shop_location_long; distance.shop_location_lat = shopInfo.shop_location_lat; distance.shop_location_format_str = shopInfo.shop_location_format_str; // aDistances[aDistances.length] = distance; aDistances.push(distance); iIdx++; if(iIdx == A_SHOP_INFO.length){ // 与所有店铺导航距离计算完毕 mylog("店铺距离数组"); mylog("'"+JSON.stringify(aDistances)+"'"); // 计算距离最近的店铺 //mw_cal_min_distance(aDistances) ; } }); }
解决办法：可以用$.each来代替for循环
1 //定义变量来计算算出了几个距离 2 var iIdx = 0; 3 //这里不使用for循环，是因为for循环中发生了异步请求之后，会导致所有异步请求成功之后的shopInfo都是最后一条数据。 4 $.each(A_SHOP_INFO, function(i,shopInfo){ 5 DRIVING.search(new AMap.LngLat(shopInfo.shop_location_long,shopInfo.shop_location_lat), new AMap.LngLat(myLnglat[0],myLnglat[1]), function(status, result){ 6 var distance = new O_DISTANCE_INFO(); 7 distance.distance = result.routes[0]["distance"]; 8 distance.shop_id = shopInfo.shop_id; 9 distance.shop_location_long = shopInfo.shop_location_long; 10 distance.shop_location_lat = shopInfo.shop_location_lat; 11 distance.shop_location_format_str = shopInfo.shop_location_format_str; 12 // aDistances[aDistances.length] = distance; 13 aDistances.push(distance); 14 iIdx++; 15 if(iIdx == A_SHOP_INFO.length){ // 与所有店铺导航距离计算完毕 16 mylog("店铺距离数组"); 17 mylog("'"+JSON.stringify(aDistances)+"'"); 18 // 计算距离最近的店铺 19 // mw_cal_min_distance(aDistances) ; 20 } 21 }); 22 });