NSLog([NSString stringWithFormat:@"%@/%@B.jpg", createDir, uuid]);//这是我的写法
应该写成
NSString *str = [NSString stringWithFormat:@"%@/%@B.jpg", createDir, uuid];
NSLog(@"%@",str);
免责声明！
本站转载的文章为个人学习借鉴使用，本站对版权不负任何法律责任。如果侵犯了您的隐私权益，请联系本站邮箱yoyou2525@163.com删除。
猜您在找
cocos2dx android版本移植时的Error format not a string literal and no format arguments解决方案
Oracle问题之literal does not match format string
error: format not a string literal and no format arguments [-Werror=format-security]
解决sqoop 导入oracle表时 --split-by参数为日期类型时的报错：ORA-01861: literal does not match format string
gdate.c:2497:7: error: format not a string literal, format string not checked [-Werror=format-nonlit
Javascript: unterminated string literal 解决方法
SyntaxError: EOL while scanning string literal的解决
The request was rejected because the URL contained a potentially malicious String ";"报错解决
解决warning: #181-D: argument is incompatible with corresponding format string conversion警告
Android studio2.2 ndk 错误 ：format not a string literal and no format arguments！