编写一个程序，求s=1+(1+2)+(1+2+3)+…+(1+2+3+…+n)的值
1 #import <Foundation/Foundation.h>
2
3 int main( int argc, const char * argv[]) {
4 @autoreleasepool {
5 int shu= 0 ,he= 0 ;
6 for ( int i= 1 ; i<= 100 ; i++) {
7 shu+=i;
8 he+=shu;
9 // printf("he is:%d\n",he);
10 }
11 printf( " he is:%d\n " ,he);
12 return 0 ;
13 }
14 }
3 int main( int argc, const char * argv[]) {
4 @autoreleasepool {
5 int shu= 0 ,he= 0 ;
6 for ( int i= 1 ; i<= 100 ; i++) {
7 shu+=i;
8 he+=shu;
9 // printf("he is:%d\n",he);
10 }
11 printf( " he is:%d\n " ,he);
12 return 0 ;
13 }
14 }
执行结果： 