例1 $connection = Yii::app()->db; $sql = "SELECT * FROM `project` ORDER BY id DESC"; $command = $connection->createCommand( $sql ...
connection Yii::app gt db sql SELECT FROM project ORDERBYidDESC command connection gt createCommand sql result command gt queryAll print r result db Yii::app gt db youhavetodefinedbconnectioninconfig ...
2012-06-10 19:36 3 7644 推薦指數:
例1 $connection = Yii::app()->db; $sql = "SELECT * FROM `project` ORDER BY id DESC"; $command = $connection->createCommand( $sql ...
查詢: 返回一個值 string strSql = "SELECT COUNT(0) FROM Person(NOLOCK)"; var quer ...
執行SQL $connection=Yii::app()->db; // 假設你已經建立了一個 "db" 連接 $sql = "SELECT * FROM tbl_log WHERE logid<:logid ...
<![CDATA[]]>這個標記所包含的內容將表示為純文本 ...
string strSql="Select * from test where id=@id"; DynamicParameters parameters = new DynamicParam ...
原文地址:https://www.cnblogs.com/wuyun-blog/p/5769096.html 需求: 1.直接執行前端傳來的任何sql語句,parameterType="String", 2.對於任何sql語句,其返回值類型無法用resultMap在xml文件里配置或者返回 ...
.net core可以執行SQL語句,但是只能生成強類型的返回結果。例如var blogs = context.Blogs.FromSql("SELECT * FROM dbo.Blogs").ToList()。而不允許返回DataSet、DataTable等弱類型。可能由於這個原因沒有實現 ...