Random r = new Random(); int num = r.NextInteger(1,101); ...
Random r = new Random(); int num = r.NextInteger(1,101); ...
int number = (int)(Math.random()*100)+1; ...
int[] intArr = new int[100]; ArrayList myList = new ArrayList(); Random rnd = new Random(); while (myList.Count < 100) { int num = rnd.Next ...
using System;namespace _02_26{ class Class_02_26 { public static void Main() { string sTemp; int iNum=new Random ().Next ()%100; //int ...
var count =100; var a = new Array(); for(var i = 0 ; i < 100 ; i++){ a[i] = i+1;}a.sort(function(){ return 0.5 - Math.random();}); for(var i ...
面试题:C#声明一个100大小的数组 随机生成1-100之间不重复的数下面是C#的实现方式,编译测试通过 ...
function sum (m,n){ var num = Math.floor(Math.random()*(m - n) + n); alert(num) } sum(1,100); 万能 公式,不管多少范围的随机数都可以取到 ...