D. 0-1 MST Ujan has a lot of useless stuff in his drawers, a considerable part of which are his mat ...
B . Character Swap Hard Version This problem is different from the easy version. In this version Ujan makes at most swaps. In addition, , and it is necessary to print swaps themselves. You can hack th ...
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D. 0-1 MST Ujan has a lot of useless stuff in his drawers, a considerable part of which are his mat ...
C. Tile Painting Ujan has been lazy lately, but now has decided to bring his yard to good shape. Fi ...
F2. Wrong Answer on test 233 (Hard Version) Your program fails again. This time it gets "Wrong answer on test 233" . This is the harder version ...
😢 😢 😢 题意:第 i 步可以挑一个数字加 i ,问你最少多少步能让两个数字相等 假设刚开始两个数字相等,然后一个数字向前走了abs(b-a)步,由等差数列求和公式,这时候我们贪心的让另外一个数字走大于等于abs(b - a)的最小步数,然后如果两数相等必须满足走的步数之和 ...
Codeforces Round #599 (Div. 2) D. 0-1 MST Description Ujan has a lot of useless stuff in his drawers, a considerable part of which are his math ...
B. Strange List 题目分析 题意:给你一个长度为n的数组和一个数字x,从第一个元素开始,如果改元素q能被x整除,那么将就在数组后面新增x个(q / x),直到遇到的元素不能被x整除,求最后数组的元素之和 让我们从样例开始入手分析:样例中的第一个情况数组a为[12],x为2,数组 ...
题目链接 A. Trip for Meal 题意 三个点之间两两有路径,分别长为\(a,b,c\),现在从第一个点出发,走\(n-1\)条边,问总路径最小值。 思路 记起始点相邻的边为\(a,b\),相对的边为\(c\). 首先肯定走\(a,b\)中的最小值(不妨设为\(a\)),到达 ...
codeforces-1287-A A. Angry Students time limit per test ...