想实现如下效果,就是分组后时间最大的那一条数据: 1、SQL SELECT * FROM ( SELECT * , ROW_NUMBER() OVER ( PARTITION ...
db.getCollection product protocol new .aggregate sort: end date : , group: id: company protocol , end date: first : ROOT , ...
2018-08-16 09:28 0 1158 推荐指数:
想实现如下效果,就是分组后时间最大的那一条数据: 1、SQL SELECT * FROM ( SELECT * , ROW_NUMBER() OVER ( PARTITION ...
with MiPriceTopOne as (select classid,max(dataTime) dataTime,max(id) as id from MiPrice group by cla ...
) A where A.Row_Sort=1 --PARTITION BY 后面接分组凭借字段(通 ...
参见:https://blog.csdn.net/zhenwei1994/article/details/83009705 ...
要求:获得 按table1_id分组,并且age最大的记录信息,即2、3、5条 方法一: select * from (select * from table2 order by age desc) as a group ...
分组中获取时间最新得一条数据 解析:根据APP_LID分组,按照FINISH_TIME不为空倒叙排序,mtime取分组中排序在第一位的数据 SELECT * FROM ( SELECT ROW_NUMBER () OVER ( PARTITION BY APP_LID ...