Based on bucket sort: Based on Quick Select 当然,还有的方法是维护一个size为k的最大堆 ...
Recursion: 返回的时候返回lca和depth,每个node如果有大于一个子节点的depth相同就返回这个node,如果有一个子节点depth更深就返回个子节点lca,这个o n 就可以了 Iteration:tree的recursion换成iteration处理,一般用stack都能解决吧 相当于手动用stack模拟recursion 。感觉这题可以是一个样的做法,换成post ord ...
2017-03-15 00:38 0 1300 推荐指数:
Based on bucket sort: Based on Quick Select 当然,还有的方法是维护一个size为k的最大堆 ...
The lowest common ancestor (LCA) of two nodes U and V in a tree is the deepest node that has both U and V as descendants. Given any two nodes ...
/lowest-common-ancestor-of-a-binary-tree-part-ii.html (1) Is the tree a BST or not? BST的话,我们就能按照BS ...
留坑 待填 一篇不错的CF博客 这篇纯讲理论的,比较清楚。 去CF上搜Gym algorithm 可以看到很多算法文章。 ...
We are given a binary tree (with root node `root`), a `target` node, and an integer value `K`. Return a list of the values of all nodes that have ...
Binary TreeDefinition: at most two children node. Binary Tree Example: 10 ==root / \ 13 ...
Count Complete Tree Nodes Given a complete binary tree, count the number of nodes. In a complete binary tree every level, except possibly the last ...
问题:给一个二叉树,写一个算法判断这个树是不是balanced。 Solution #1. 第一次遇到这个问题时我的解法,如下: 写了一个getDepth()函数,访问每个节点都要 ...