Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists ...
题目: Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 没事来做做题,该题目是说两个排序好的链表组合起来,依然是排序好的,即链表的值从小到大。 代码: 于是乎,新建 ...
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Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists ...
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists ...
问题:有序合并两个有序链表分析:归并排序的合并部分 class Solution { public: ListNode *mergeTwoLists(ListNode *l1, Lis ...
就是合并两个有序链表了,递归解妥妥儿的。 ListNode *mergeTwoLists(ListNode *l1, ListNode *l2) { ...
原题地址:https://oj.leetcode.com/problems/merge-two-sorted-lists/ 题意:Merge two sorted linked lists and return it as a new list. The new list should ...
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 维护一个新 ...
题目: 给出两个排序的单链表,合并两个单链表,返回合并后的结果; 解题思路: 解法还是很简单的,但是需要注意以下几点: 1. 如果两个链表都空,则返回null; 2. 如果链表1空,则返回 ...
题目:Merge Two Sorted Lists 简单题,只要对两个链表中的元素进行比较,然后移动即可,只要对链表的增删操作熟悉,几分钟就可以写出来,代码如下: 这其中要注意一点,即要记得处理一个链表为空,另一个不为空的情况,如{}, {0} -- > ...