原文:[LeetCode] 139. Word Break 拆分词句

Given anon emptystringsand a dictionarywordDictcontaining a list ofnon emptywords, determine ifscan be segmented into a space separated sequence of one or more dictionary words. Note: The same word i ...

2015-01-29 04:59 12 24123 推荐指数:

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[LeetCode] Word Break II 拆分词句之二

Given a non-empty string s and a dictionary wordDict containing a list of non-empty words, add spaces in s to construct a sentence where each word ...

Mon Jun 15 13:49:00 CST 2015 7 19658
leetcode139.单词拆分

给定一个非空字符串 s 和一个包含非空单词列表的字典 wordDict,判定 s 是否可以被空格拆分为一个或多个在字典中出现的单词。 思路分析: (1)比较容易想到的解法是,从字符串 s 开头处开始匹配,若匹配到字典里的字符串,则继续匹配剩下的字符串。这样递归下去,直到找到一个可行的序列或尝试 ...

Sun Aug 26 20:31:00 CST 2018 0 3113
[LeetCode] 140. Word Break II 单词拆分II

Given a non-empty string s and a dictionary wordDict containing a list of non-empty words, add spaces in s to construct a sentence where each word ...

Mon Mar 05 23:04:00 CST 2018 0 1613
[leetcode]Word Break @ Python

原题地址:https://oj.leetcode.com/problems/word-break/ 题意: Given a string s and a dictionary of words dict, determine if s can be segmented ...

Fri May 30 18:53:00 CST 2014 1 5693
Word Break leetcode java

words. For example, given s = "leetcode", dict = ["le ...

Tue Jul 29 17:27:00 CST 2014 0 2775
[Leetcode] Word Break II

Given a string s and a dictionary of words dict, add spaces in s to construct a sentence where each word is a valid dictionary word. Return all ...

Wed Apr 23 01:16:00 CST 2014 0 2963
 
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