题目: 给出两个排序的单链表,合并两个单链表,返回合并后的结果; 解题思路: 解法还是很简单的,但是需要注意以下几点: 1. 如果两个链表都空,则返回null; 2. 如果链表1空,则返回链表2的头节点;反之,如果链表2为空,则返回链表1的头节点; 3. 两个链表都不空的情况下 ...
题目:Merge Two Sorted Lists 简单题,只要对两个链表中的元素进行比较,然后移动即可,只要对链表的增删操作熟悉,几分钟就可以写出来,代码如下: 这其中要注意一点,即要记得处理一个链表为空,另一个不为空的情况,如 , gt ,当然上面的写法多少啰嗦了一些,可以简写。 ...
2014-10-06 16:08 0 2376 推荐指数:
题目: 给出两个排序的单链表,合并两个单链表,返回合并后的结果; 解题思路: 解法还是很简单的,但是需要注意以下几点: 1. 如果两个链表都空,则返回null; 2. 如果链表1空,则返回链表2的头节点;反之,如果链表2为空,则返回链表1的头节点; 3. 两个链表都不空的情况下 ...
1. 题目描述 Merge two sorted linked lists and return it as a new sorted list. The new list should be made by splicing together the nodes of the first ...
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists ...
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 维护一个新 ...
题目: Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists ...
原题地址:https://oj.leetcode.com/problems/merge-two-sorted-lists/ 题意:Merge two sorted linked lists and return it as a new list. The new list should ...
题目: Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists ...
问题:有序合并两个有序链表分析:归并排序的合并部分 class Solution { public: ListNode *mergeTwoLists(ListNode *l1, ListNode *l2) { ListNode *helper=new ...