Partition List leetcode java
题目： Given a linked list and a value x, partition it such that all nodes less than x come before nodes greater than or equal to x. You should ...
原文：Leetcode: Partition List
思路: . 空间复杂度为 o n 解法. 创建两个链表, 分别记录大于 x 和小于 x 的节点, 最后合并 . o 的空间复杂度解法. 四个指针, 分别指向小于 x 部分链表的头, 尾, 指向大于 x 部分链表的头, 尾 总结: . 使用 dummyNode 减少判断 代码: class Solution public: ListNode partition ListNode head, int ...
2013-12-05 17:20 0 2432 推荐指数：
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