[leetcode]Word Break @ Python
原题地址：https://oj.leetcode.com/problems/word-break/ 题意： Given a string s and a dictionary of words dict, determine if s can be segmented ...
原文：[leetcode]Word Break
LeetCode越来越大姨妈了，Submit上去又卡住了，先假设通过了吧。这道题拿到思考先是递归，然后有重复子状态，显然是DP。用f i,j 表示字符串S从i到j的子串是否可分割，则有：f ,n f ,i amp amp f i,n 。但是如果自底向上求的话会计算很多不需要的，比如leet已经在字典里了，很多情况下就不需要计算下面的l,e,e,t了，所以自顶向下递归 备忘录会是更快的方法。 imp ...
2013-10-16 00:19 2 2957 推荐指数：
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