例1 $connection = Yii::app()->db; $sql = "SELECT * FROM `project` ORDER BY id DESC"; $command = $connection->createCommand( $sql ...
connection Yii::app gt db sql SELECT FROM project ORDERBYidDESC command connection gt createCommand sql result command gt queryAll print r result db Yii::app gt db youhavetodefinedbconnectioninconfig ...
2012-06-10 19:36 3 7644 推荐指数:
例1 $connection = Yii::app()->db; $sql = "SELECT * FROM `project` ORDER BY id DESC"; $command = $connection->createCommand( $sql ...
查询: 返回一个值 string strSql = "SELECT COUNT(0) FROM Person(NOLOCK)"; var quer ...
执行SQL $connection=Yii::app()->db; // 假设你已经建立了一个 "db" 连接 $sql = "SELECT * FROM tbl_log WHERE logid<:logid ...
<![CDATA[]]>这个标记所包含的内容将表示为纯文本 ...
string strSql="Select * from test where id=@id"; DynamicParameters parameters = new DynamicParam ...
原文地址:https://www.cnblogs.com/wuyun-blog/p/5769096.html 需求: 1.直接执行前端传来的任何sql语句,parameterType="String", 2.对于任何sql语句,其返回值类型无法用resultMap在xml文件里配置或者返回 ...
.net core可以执行SQL语句,但是只能生成强类型的返回结果。例如var blogs = context.Blogs.FromSql("SELECT * FROM dbo.Blogs").ToList()。而不允许返回DataSet、DataTable等弱类型。可能由于这个原因没有实现 ...